Optimal. Leaf size=208 \[ \frac{\left (8 a^2-24 a b+3 b^2\right ) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{24 a^2 f}+\frac{\left (8 a^2-24 a b+3 b^2\right ) \sqrt{a+b \sin ^2(e+f x)}}{8 a f}-\frac{\left (8 a^2-24 a b+3 b^2\right ) \tanh ^{-1}\left (\frac{\sqrt{a+b \sin ^2(e+f x)}}{\sqrt{a}}\right )}{8 \sqrt{a} f}+\frac{(8 a-b) \csc ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{8 a^2 f}-\frac{\csc ^4(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{4 a f} \]
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Rubi [A] time = 0.191996, antiderivative size = 208, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.24, Rules used = {3194, 89, 78, 50, 63, 208} \[ \frac{\left (8 a^2-24 a b+3 b^2\right ) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{24 a^2 f}+\frac{\left (8 a^2-24 a b+3 b^2\right ) \sqrt{a+b \sin ^2(e+f x)}}{8 a f}-\frac{\left (8 a^2-24 a b+3 b^2\right ) \tanh ^{-1}\left (\frac{\sqrt{a+b \sin ^2(e+f x)}}{\sqrt{a}}\right )}{8 \sqrt{a} f}+\frac{(8 a-b) \csc ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{8 a^2 f}-\frac{\csc ^4(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{4 a f} \]
Antiderivative was successfully verified.
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Rule 3194
Rule 89
Rule 78
Rule 50
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \cot ^5(e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{(1-x)^2 (a+b x)^{3/2}}{x^3} \, dx,x,\sin ^2(e+f x)\right )}{2 f}\\ &=-\frac{\csc ^4(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{4 a f}+\frac{\operatorname{Subst}\left (\int \frac{\left (\frac{1}{2} (-8 a+b)+2 a x\right ) (a+b x)^{3/2}}{x^2} \, dx,x,\sin ^2(e+f x)\right )}{4 a f}\\ &=\frac{(8 a-b) \csc ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{8 a^2 f}-\frac{\csc ^4(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{4 a f}+\frac{\left (2 a^2+\frac{3}{4} b (-8 a+b)\right ) \operatorname{Subst}\left (\int \frac{(a+b x)^{3/2}}{x} \, dx,x,\sin ^2(e+f x)\right )}{4 a^2 f}\\ &=\frac{\left (8 a^2-3 (8 a-b) b\right ) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{24 a^2 f}+\frac{(8 a-b) \csc ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{8 a^2 f}-\frac{\csc ^4(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{4 a f}+\frac{\left (2 a^2+\frac{3}{4} b (-8 a+b)\right ) \operatorname{Subst}\left (\int \frac{\sqrt{a+b x}}{x} \, dx,x,\sin ^2(e+f x)\right )}{4 a f}\\ &=\frac{\left (8 a^2-3 (8 a-b) b\right ) \sqrt{a+b \sin ^2(e+f x)}}{8 a f}+\frac{\left (8 a^2-3 (8 a-b) b\right ) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{24 a^2 f}+\frac{(8 a-b) \csc ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{8 a^2 f}-\frac{\csc ^4(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{4 a f}+\frac{\left (2 a^2+\frac{3}{4} b (-8 a+b)\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+b x}} \, dx,x,\sin ^2(e+f x)\right )}{4 f}\\ &=\frac{\left (8 a^2-3 (8 a-b) b\right ) \sqrt{a+b \sin ^2(e+f x)}}{8 a f}+\frac{\left (8 a^2-3 (8 a-b) b\right ) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{24 a^2 f}+\frac{(8 a-b) \csc ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{8 a^2 f}-\frac{\csc ^4(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{4 a f}+\frac{\left (2 a^2+\frac{3}{4} b (-8 a+b)\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{a}{b}+\frac{x^2}{b}} \, dx,x,\sqrt{a+b \sin ^2(e+f x)}\right )}{2 b f}\\ &=-\frac{\left (8 a^2-3 (8 a-b) b\right ) \tanh ^{-1}\left (\frac{\sqrt{a+b \sin ^2(e+f x)}}{\sqrt{a}}\right )}{8 \sqrt{a} f}+\frac{\left (8 a^2-3 (8 a-b) b\right ) \sqrt{a+b \sin ^2(e+f x)}}{8 a f}+\frac{\left (8 a^2-3 (8 a-b) b\right ) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{24 a^2 f}+\frac{(8 a-b) \csc ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{8 a^2 f}-\frac{\csc ^4(e+f x) \left (a+b \sin ^2(e+f x)\right )^{5/2}}{4 a f}\\ \end{align*}
Mathematica [A] time = 0.842136, size = 123, normalized size = 0.59 \[ \frac{\sqrt{a} \sqrt{a+b \sin ^2(e+f x)} \left (8 \left (4 a+b \sin ^2(e+f x)-6 b\right )+3 (8 a-5 b) \csc ^2(e+f x)-6 a \csc ^4(e+f x)\right )-3 \left (8 a^2-24 a b+3 b^2\right ) \tanh ^{-1}\left (\frac{\sqrt{a+b \sin ^2(e+f x)}}{\sqrt{a}}\right )}{24 \sqrt{a} f} \]
Antiderivative was successfully verified.
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Maple [A] time = 1.688, size = 280, normalized size = 1.4 \begin{align*}{\frac{b \left ( \sin \left ( fx+e \right ) \right ) ^{2}}{3\,f}\sqrt{a+b \left ( \sin \left ( fx+e \right ) \right ) ^{2}}}+{\frac{4\,a}{3\,f}\sqrt{a+b \left ( \sin \left ( fx+e \right ) \right ) ^{2}}}-2\,{\frac{b\sqrt{a+b \left ( \sin \left ( fx+e \right ) \right ) ^{2}}}{f}}-{\frac{a}{4\,f \left ( \sin \left ( fx+e \right ) \right ) ^{4}}\sqrt{a+b \left ( \sin \left ( fx+e \right ) \right ) ^{2}}}-{\frac{5\,b}{8\,f \left ( \sin \left ( fx+e \right ) \right ) ^{2}}\sqrt{a+b \left ( \sin \left ( fx+e \right ) \right ) ^{2}}}-{\frac{3\,{b}^{2}}{8\,f}\ln \left ({\frac{1}{\sin \left ( fx+e \right ) } \left ( 2\,a+2\,\sqrt{a}\sqrt{a+b \left ( \sin \left ( fx+e \right ) \right ) ^{2}} \right ) } \right ){\frac{1}{\sqrt{a}}}}-{\frac{1}{f}{a}^{{\frac{3}{2}}}\ln \left ({\frac{1}{\sin \left ( fx+e \right ) } \left ( 2\,a+2\,\sqrt{a}\sqrt{a+b \left ( \sin \left ( fx+e \right ) \right ) ^{2}} \right ) } \right ) }+3\,{\frac{\sqrt{a}b}{f}\ln \left ({\frac{2\,a+2\,\sqrt{a}\sqrt{a+b \left ( \sin \left ( fx+e \right ) \right ) ^{2}}}{\sin \left ( fx+e \right ) }} \right ) }+{\frac{a}{f \left ( \sin \left ( fx+e \right ) \right ) ^{2}}\sqrt{a+b \left ( \sin \left ( fx+e \right ) \right ) ^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 12.9466, size = 1089, normalized size = 5.24 \begin{align*} \left [\frac{3 \,{\left ({\left (8 \, a^{2} - 24 \, a b + 3 \, b^{2}\right )} \cos \left (f x + e\right )^{4} - 2 \,{\left (8 \, a^{2} - 24 \, a b + 3 \, b^{2}\right )} \cos \left (f x + e\right )^{2} + 8 \, a^{2} - 24 \, a b + 3 \, b^{2}\right )} \sqrt{a} \log \left (\frac{2 \,{\left (b \cos \left (f x + e\right )^{2} + 2 \, \sqrt{-b \cos \left (f x + e\right )^{2} + a + b} \sqrt{a} - 2 \, a - b\right )}}{\cos \left (f x + e\right )^{2} - 1}\right ) - 2 \,{\left (8 \, a b \cos \left (f x + e\right )^{6} - 8 \,{\left (4 \, a^{2} - 3 \, a b\right )} \cos \left (f x + e\right )^{4} +{\left (88 \, a^{2} - 87 \, a b\right )} \cos \left (f x + e\right )^{2} - 50 \, a^{2} + 55 \, a b\right )} \sqrt{-b \cos \left (f x + e\right )^{2} + a + b}}{48 \,{\left (a f \cos \left (f x + e\right )^{4} - 2 \, a f \cos \left (f x + e\right )^{2} + a f\right )}}, \frac{3 \,{\left ({\left (8 \, a^{2} - 24 \, a b + 3 \, b^{2}\right )} \cos \left (f x + e\right )^{4} - 2 \,{\left (8 \, a^{2} - 24 \, a b + 3 \, b^{2}\right )} \cos \left (f x + e\right )^{2} + 8 \, a^{2} - 24 \, a b + 3 \, b^{2}\right )} \sqrt{-a} \arctan \left (\frac{\sqrt{-b \cos \left (f x + e\right )^{2} + a + b} \sqrt{-a}}{a}\right ) -{\left (8 \, a b \cos \left (f x + e\right )^{6} - 8 \,{\left (4 \, a^{2} - 3 \, a b\right )} \cos \left (f x + e\right )^{4} +{\left (88 \, a^{2} - 87 \, a b\right )} \cos \left (f x + e\right )^{2} - 50 \, a^{2} + 55 \, a b\right )} \sqrt{-b \cos \left (f x + e\right )^{2} + a + b}}{24 \,{\left (a f \cos \left (f x + e\right )^{4} - 2 \, a f \cos \left (f x + e\right )^{2} + a f\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \sin \left (f x + e\right )^{2} + a\right )}^{\frac{3}{2}} \cot \left (f x + e\right )^{5}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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